博客
关于我
强烈建议你试试无所不能的chatGPT,快点击我
基础训练
阅读量:2242 次
发布时间:2019-05-09

本文共 3616 字,大约阅读时间需要 12 分钟。

基础训练


  1. Who's in the Middle

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) 
Total Submission(s): 4184 Accepted Submission(s): 1543

Problem Description 
FJ is surveying his herd to find the most average cow. He wants to know how much milk this ‘median’ cow gives: half of the cows give as much or more than the median; half give as much or less.

Given an odd number of cows N (1 <= N < 10,000) and their milk output (1..1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.

Input

  • Line 1: A single integer N

  • Lines 2..N+1: Each line contains a single integer that is the milk output of one cow.

Output

  • Line 1: A single integer that is the median milk output.

Sample Input 





5

Sample Output 
3

Hint

INPUT DETAILS:

Five cows with milk outputs of 1..5

OUTPUT DETAILS:

1 and 2 are below 3; 4 and 5 are above 3.

解题思路:先排序,照中位数 
用到算法中的函数sort

#include 
#include
#include
using namespace std; int main() {
vector
v; int n = 0; while (scanf("%d",&n) == 1) {
v.resize(n); for (int i = 0; i < n; ++i) {
scanf("%d",&v[i]); } sort(v.begin(),v.end()); printf("%d\n",v[(v.size()+1) / 2 - 1]); v.clear(); } return 0; }


  1. Ignatius and the Princess IV 

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32767 K (Java/Others) 
Total Submission(s): 32290 Accepted Submission(s): 13919 
Problem Description 
“OK, you are not too bad, em… But you can never pass the next test.” feng5166 says.

“I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers.” feng5166 says.

“But what is the characteristic of the special integer?” Ignatius asks.

“The integer will appear at least (N+1)/2 times. If you can’t find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha…..” feng5166 says.

Can you find the special integer for Ignatius?

Input 
The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.

Output 
For each test case, you have to output only one line which contains the special number you have found.

Sample Input 

1 3 2 3 3 
11 
1 1 1 1 1 5 5 5 5 5 5 

1 1 1 1 1 1 1

Sample Output 


1

解题思路,使用STL的map存储数据,将map中的second当作计数器,若插入不成功(即map中存在key值),insert返回一个迭代器(iterator)指向当前map中的pair结构体,该结构体有两个数据,分别是first和second,我们将second当作计数器,即该key值出现的次数,最后遍历一遍找到map中最大的second对应的key。

#include 
#include
#include
using namespace std; int main() {
map
mp; size_t n = 0; while(scanf("%d",&n) == 1) {
int num = 1; int value = 0; int max = 0; int spnum = 0; for (int i = 0; i < n; ++i) {
scanf("%d",&value); if (! mp.insert(make_pair(value,num)).second ) mp[value]++; } map
::iterator it = mp.begin(); for (;it != mp.end();++it) {
if(it->second > max) {
max = it->second; spnum = it->first; } } printf("%d\n",spnum); mp.clear(); } return 0; }

转载地址:http://vtgbb.baihongyu.com/

你可能感兴趣的文章
了解 Sklearn 的数据集
查看>>
如何选择优化器 optimizer
查看>>
一文了解强化学习
查看>>
CART 分类与回归树
查看>>
seq2seq 的 keras 实现
查看>>
seq2seq 入门
查看>>
什么是 Dropout
查看>>
用 LSTM 做时间序列预测的一个小例子
查看>>
用 LSTM 来做一个分类小问题
查看>>
详解 LSTM
查看>>
按时间轴简述九大卷积神经网络
查看>>
详解循环神经网络(Recurrent Neural Network)
查看>>
为什么要用交叉验证
查看>>
用学习曲线 learning curve 来判别过拟合问题
查看>>
用验证曲线 validation curve 选择超参数
查看>>
用 Grid Search 对 SVM 进行调参
查看>>
用 Pipeline 将训练集参数重复应用到测试集
查看>>
PCA 的数学原理和可视化效果
查看>>
机器学习中常用评估指标汇总
查看>>
什么是 ROC AUC
查看>>